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4x^2=-8x-4
We move all terms to the left:
4x^2-(-8x-4)=0
We get rid of parentheses
4x^2+8x+4=0
a = 4; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{8}=-1$
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